What are the solutions to the equation solvefor x,x^2+px+q=0 ?

The solutions to the equation solvefor x,x^2+px+q=0 are x=(-p+sqrt(p^2-4q))/2 ,x=(-p-sqrt(p^2-4q))/2

Find the zeros of solvefor x,x^2+px+q=0

The zeros of solvefor x,x^2+px+q=0 are x=(-p+sqrt(p^2-4q))/2 ,x=(-p-sqrt(p^2-4q))/2

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solve for

x, x^{2} + p x + q = 0

x = \frac{- p + p ^{2} - 4 q}{2}, x = \frac{- p - p ^{2} - 4 q}{2}

Solution steps

x^{2} + p x + q = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- p \pm p ^{2} - 4 \cdot 1 \cdot q}{2 \cdot 1}

Simplify

p^{2} - 4 \cdot 1 \cdot q : p^{2} - 4 q

x_{1, 2} = \frac{- p \pm p ^{2} - 4 q}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- p + p ^{2} - 4 q}{2 \cdot 1}, x_{2} = \frac{- p - p ^{2} - 4 q}{2 \cdot 1}

x = \frac{- p + p ^{2} - 4 q}{2 \cdot 1} : \frac{- p + p ^{2} - 4 q}{2}

x = \frac{- p - p ^{2} - 4 q}{2 \cdot 1} : \frac{- p - p ^{2} - 4 q}{2}

The solutions to the quadratic equation are:

x = \frac{- p + p ^{2} - 4 q}{2}, x = \frac{- p - p ^{2} - 4 q}{2}

5 x - 1 = x^{2} + 2 x + 1

x^{2} + 9 x - 10 = 0

15 (- 3 x + 2)^{2} + 4 (- 3 x + 2) - 3 = 0

2 x^{2} = 8 x - 5

2 x^{2} = 8 x - 8

What are the solutions to the equation solvefor x,x^2+px+q=0 ?
The solutions to the equation solvefor x,x^2+px+q=0 are x=(-p+sqrt(p^2-4q))/2 ,x=(-p-sqrt(p^2-4q))/2
Find the zeros of solvefor x,x^2+px+q=0
The zeros of solvefor x,x^2+px+q=0 are x=(-p+sqrt(p^2-4q))/2 ,x=(-p-sqrt(p^2-4q))/2