What are the solutions to the equation 2*x*(-x)=-1 ?

The solutions to the equation 2*x*(-x)=-1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of 2*x*(-x)=-1

The zeros of 2*x*(-x)=-1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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2 \cdot x \cdot (- x) = - 1

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

2 x (- x) = - 1

Simplify

- 2 x^{2} = - 1

Divide both sides by

- 2

\frac{- 2 x ^{2}}{- 2} = \frac{- 1}{- 2}

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

0 = \frac{1}{2} x^{2} - 3 x - 2

5 x^{2} - 16 x - 22 = 3 x^{2} - 17

- 3 x^{2} - 6 x + 2 = 0

(- t)^{2} - 4 \cdot 3 \cdot (- 2) = 1

x, 3 x^{2} + 2 y^{2} + e^{5 y} = 13

What are the solutions to the equation 2*x*(-x)=-1 ?
The solutions to the equation 2*x*(-x)=-1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of 2*x*(-x)=-1
The zeros of 2*x*(-x)=-1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))