What are the solutions to the equation -1/4 x^2+4x-6=0 ?

The solutions to the equation -1/4 x^2+4x-6=0 are x=2(4-sqrt(10)),x=2(4+sqrt(10))

Find the zeros of -1/4 x^2+4x-6=0

The zeros of -1/4 x^2+4x-6=0 are x=2(4-sqrt(10)),x=2(4+sqrt(10))

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- \frac{1}{4} x^{2} + 4 x - 6 = 0

x = 2 (4 - 10), x = 2 (4 + 10)

Decimal Notation

x = 1.67544 \dots, x = 14.32455 \dots

Solution steps

- \frac{1}{4} x^{2} + 4 x - 6 = 0

Multiply both sides by

4

- x^{2} + 16 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 1 ) ( - 24 )}{2 ( - 1 )}

1 6^{2} - 4 (- 1) (- 24) = 410

x_{1, 2} = \frac{- 16 \pm 4 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 16 + 4 10}{2 ( - 1 )}, x_{2} = \frac{- 16 - 4 10}{2 ( - 1 )}

x = \frac{- 16 + 4 10}{2 ( - 1 )} : 2 (4 - 10)

x = \frac{- 16 - 4 10}{2 ( - 1 )} : 2 (4 + 10)

The solutions to the quadratic equation are:

x = 2 (4 - 10), x = 2 (4 + 10)

5 x^{2} - 15 x - 10 = 20

- 6 x^{2} + 26 x + 20 = 0

2000 + 5 x^{2} - 200 x = 1192.4

x^{2} + 7 x - 800 = 0

x, y + x cos (y) = x^{2} y

What are the solutions to the equation -1/4 x^2+4x-6=0 ?
The solutions to the equation -1/4 x^2+4x-6=0 are x=2(4-sqrt(10)),x=2(4+sqrt(10))
Find the zeros of -1/4 x^2+4x-6=0
The zeros of -1/4 x^2+4x-6=0 are x=2(4-sqrt(10)),x=2(4+sqrt(10))