What is factor j^2+24j-25 ?

The solution to factor j^2+24j-25 is (j-1)(j+25)

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factor j^2+24j-25

factor

j^{2} + 24 j - 25

(j - 1) (j + 25)

Solution steps

j^{2} + 24 j - 25

Break the expression into groups

= (j^{2} - j) + (25 j - 25)

Factor out

j

from

j^{2} - j : j (j - 1)

Factor out

25

from

25 j - 25 : 25 (j - 1)

= j (j - 1) + 25 (j - 1)

Factor out common term

j - 1

= (j - 1) (j + 25)

\frac{4 x ^{5} y ^{7}}{8 x ^{2} y}

f = 1^{2} - 3

- 2147 - 108

ln (4) - ln (1)

8 \leq 8