What are the solutions to the equation -x^2+2x=6 ?

The solutions to the equation -x^2+2x=6 are x=1-sqrt(5)i,x=1+sqrt(5)i

Find the zeros of -x^2+2x=6

The zeros of -x^2+2x=6 are x=1-sqrt(5)i,x=1+sqrt(5)i

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- x^{2} + 2 x = 6

x = 1 - 5 i, x = 1 + 5 i

Solution steps

- x^{2} + 2 x = 6

Move

6

to the left side

- x^{2} + 2 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

Simplify

2^{2} - 4 (- 1) (- 6) : 25 i

x_{1, 2} = \frac{- 2 \pm 2 5 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 5 i}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 5 i}{2 ( - 1 )}

x = \frac{- 2 + 2 5 i}{2 ( - 1 )} : 1 - 5 i

x = \frac{- 2 - 2 5 i}{2 ( - 1 )} : 1 + 5 i

The solutions to the quadratic equation are:

x = 1 - 5 i, x = 1 + 5 i

5 x^{2} - 16 x + 16 = 0

x^{2} - 9.73 x + 4.5 = 0

x, x^{2} + 5 x - 5 a t x = 2

5 k^{2} + 14 k + 8 = 0

x = - 200 x^{2} + 40000 x + 8

What are the solutions to the equation -x^2+2x=6 ?
The solutions to the equation -x^2+2x=6 are x=1-sqrt(5)i,x=1+sqrt(5)i
Find the zeros of -x^2+2x=6
The zeros of -x^2+2x=6 are x=1-sqrt(5)i,x=1+sqrt(5)i