What are the solutions to the equation (4k+5)(k+7)=0 ?

The solutions to the equation (4k+5)(k+7)=0 are k=-5/4 ,k=-7

Find the zeros of (4k+5)(k+7)=0

The zeros of (4k+5)(k+7)=0 are k=-5/4 ,k=-7

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(4 k + 5) (k + 7) = 0

k = - \frac{5}{4}, k = - 7

Decimal Notation

k = - 1.25, k = - 7

Solution steps

(4 k + 5) (k + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 k + 5 = 0 or k + 7 = 0

Solve

4 k + 5 = 0 : k = - \frac{5}{4}

Solve

k + 7 = 0 : k = - 7

The solutions to the quadratic equation are:

k = - \frac{5}{4}, k = - 7

x, x^{2} + y^{2} - x + y + 1 = 0

z^{2} - z - 12 = 0

4 x^{2} = - 9 x + 1

39 + 10 x - x^{2}

96 x^{2} + 1095 x + 1 = 0

What are the solutions to the equation (4k+5)(k+7)=0 ?
The solutions to the equation (4k+5)(k+7)=0 are k=-5/4 ,k=-7
Find the zeros of (4k+5)(k+7)=0
The zeros of (4k+5)(k+7)=0 are k=-5/4 ,k=-7