What are the solutions to the equation x^2-4x-2=3 ?

The solutions to the equation x^2-4x-2=3 are x=5,x=-1

Find the zeros of x^2-4x-2=3

The zeros of x^2-4x-2=3 are x=5,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 4 x - 2 = 3

x = 5, x = - 1

Solution steps

x^{2} - 4 x - 2 = 3

Move

3

to the left side

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

x^{2} = 4 x - 14

24 x^{2} - 28 x + 13 = 0

x^{2} = 55

14 x = 8 x^{2}

9 (3.5)^{2} - 5 (3.5) y + 7 y^{2} = 120

What are the solutions to the equation x^2-4x-2=3 ?
The solutions to the equation x^2-4x-2=3 are x=5,x=-1
Find the zeros of x^2-4x-2=3
The zeros of x^2-4x-2=3 are x=5,x=-1