What are the solutions to the equation 0.18=(1+j/2)^2-1 ?

The solutions to the equation 0.18=(1+j/2)^2-1 are j=0.17255…,j=-4.17255…

Find the zeros of 0.18=(1+j/2)^2-1

The zeros of 0.18=(1+j/2)^2-1 are j=0.17255…,j=-4.17255…

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0.18 = (1 + \frac{j}{2})^{2} - 1

j = 0.17255 \dots, j = - 4.17255 \dots

Solution steps

0.18 = (1 + \frac{j}{2})^{2} - 1

Switch sides

(1 + \frac{j}{2})^{2} - 1 = 0.18

Move

1

to the right side

(1 + \frac{j}{2})^{2} = 1.18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 + \frac{j}{2} = 1.18 : j = 0.17255 \dots

Solve

1 + \frac{j}{2} = - 1.18 : j = - 4.17255 \dots

The solutions to the quadratic equation are:

j = 0.17255 \dots, j = - 4.17255 \dots

3 x^{2} - 1 x = 0

- x^{2} + 625 = 0

x, 8 y^{3} = x^{2}

2 x^{2} + 12 x - 182 = 0

x^{2} + 8 x - 17 = 0

What are the solutions to the equation 0.18=(1+j/2)^2-1 ?
The solutions to the equation 0.18=(1+j/2)^2-1 are j=0.17255…,j=-4.17255…
Find the zeros of 0.18=(1+j/2)^2-1
The zeros of 0.18=(1+j/2)^2-1 are j=0.17255…,j=-4.17255…