What are the solutions to the equation 4.6y^2+3.5y-1.75=0 ?

The solutions to the equation 4.6y^2+3.5y-1.75=0 are y=(-35+sqrt(4445))/(92),y=-(35+sqrt(4445))/(92)

Find the zeros of 4.6y^2+3.5y-1.75=0

The zeros of 4.6y^2+3.5y-1.75=0 are y=(-35+sqrt(4445))/(92),y=-(35+sqrt(4445))/(92)

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4.6 y^{2} + 3.5 y - 1.75 = 0

y = \frac{- 35 + 4445}{92}, y = - \frac{35 + 4445}{92}

Decimal Notation

y = 0.34424 \dots, y = - 1.10511 \dots

Solution steps

4.6 y^{2} + 3.5 y - 1.75 = 0

Multiply both sides by

100

460 y^{2} + 350 y - 175 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 350 \pm 35 0 ^{2} - 4 \cdot 460 ( - 175 )}{2 \cdot 460}

35 0^{2} - 4 \cdot 460 (- 175) = 104445

y_{1, 2} = \frac{- 350 \pm 10 4445}{2 \cdot 460}

Separate the solutions

y_{1} = \frac{- 350 + 10 4445}{2 \cdot 460}, y_{2} = \frac{- 350 - 10 4445}{2 \cdot 460}

y = \frac{- 350 + 10 4445}{2 \cdot 460} : \frac{- 35 + 4445}{92}

y = \frac{- 350 - 10 4445}{2 \cdot 460} : - \frac{35 + 4445}{92}

The solutions to the quadratic equation are:

y = \frac{- 35 + 4445}{92}, y = - \frac{35 + 4445}{92}

\frac{2}{3} (x - 4) (x + 5) = 1

y, x^{2} y + x^{3} y^{2} = 2

t, d (t) = - 9.81 t^{2} + 10 t m

4 z^{2} - r^{2} = 4

- 9 = - 23 + 7 x^{2}

What are the solutions to the equation 4.6y^2+3.5y-1.75=0 ?
The solutions to the equation 4.6y^2+3.5y-1.75=0 are y=(-35+sqrt(4445))/(92),y=-(35+sqrt(4445))/(92)
Find the zeros of 4.6y^2+3.5y-1.75=0
The zeros of 4.6y^2+3.5y-1.75=0 are y=(-35+sqrt(4445))/(92),y=-(35+sqrt(4445))/(92)