What are the solutions to the equation 2x^2-7x-13=-10 ?

The solutions to the equation 2x^2-7x-13=-10 are x=(7+sqrt(73))/4 ,x=(7-sqrt(73))/4

Find the zeros of 2x^2-7x-13=-10

The zeros of 2x^2-7x-13=-10 are x=(7+sqrt(73))/4 ,x=(7-sqrt(73))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 7 x - 13 = - 10

x = \frac{7 + 73}{4}, x = \frac{7 - 73}{4}

Decimal Notation

x = 3.88600 \dots, x = - 0.38600 \dots

Solution steps

2 x^{2} - 7 x - 13 = - 10

Move

10

to the left side

2 x^{2} - 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 3) = 73

x_{1, 2} = \frac{- ( - 7 ) \pm 73}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 73}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 73}{2 \cdot 2}

x = \frac{- ( - 7 ) + 73}{2 \cdot 2} : \frac{7 + 73}{4}

x = \frac{- ( - 7 ) - 73}{2 \cdot 2} : \frac{7 - 73}{4}

The solutions to the quadratic equation are:

x = \frac{7 + 73}{4}, x = \frac{7 - 73}{4}

\frac{1}{3} (lo g_{3} (m) - lo g_{3} (n))

\frac{y ^{2}}{25} = 3

19.6 n = 3.92

1 < 5 x + 6 \leq 16

\frac{4}{5} a \leq - 12

What are the solutions to the equation 2x^2-7x-13=-10 ?
The solutions to the equation 2x^2-7x-13=-10 are x=(7+sqrt(73))/4 ,x=(7-sqrt(73))/4
Find the zeros of 2x^2-7x-13=-10
The zeros of 2x^2-7x-13=-10 are x=(7+sqrt(73))/4 ,x=(7-sqrt(73))/4