What are the solutions to the equation -2(x-3)^2+8=10 ?

The solutions to the equation -2(x-3)^2+8=10 are x=i+3,x=-i+3

Find the zeros of -2(x-3)^2+8=10

The zeros of -2(x-3)^2+8=10 are x=i+3,x=-i+3

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- 2 (x - 3)^{2} + 8 = 10

x = i + 3, x = - i + 3

Solution steps

- 2 (x - 3)^{2} + 8 = 10

Move

8

to the right side

- 2 (x - 3)^{2} = 2

Divide both sides by

- 2

(x - 3)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - 1 : x = i + 3

Solve

x - 3 = - - 1 : x = - i + 3

The solutions to the quadratic equation are:

x = i + 3, x = - i + 3

v, E = m g h + \frac{m v ^{2}}{2}

18 - x^{2} = 0

m, m^{2} + n^{2} = 10

- 9 x^{2} + 36 x = 38

x^{2} - \frac{1}{3} x - \frac{2}{9} = 0

What are the solutions to the equation -2(x-3)^2+8=10 ?
The solutions to the equation -2(x-3)^2+8=10 are x=i+3,x=-i+3
Find the zeros of -2(x-3)^2+8=10
The zeros of -2(x-3)^2+8=10 are x=i+3,x=-i+3