What are the solutions to the equation 5a^2+4a=-2+2a ?

The solutions to the equation 5a^2+4a=-2+2a are a=-1/5+i 3/5 ,a=-1/5-i 3/5

Find the zeros of 5a^2+4a=-2+2a

The zeros of 5a^2+4a=-2+2a are a=-1/5+i 3/5 ,a=-1/5-i 3/5

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5 a^{2} + 4 a = - 2 + 2 a

a = - \frac{1}{5} + i \frac{3}{5}, a = - \frac{1}{5} - i \frac{3}{5}

Solution steps

5 a^{2} + 4 a = - 2 + 2 a

Move

2 a

to the left side

5 a^{2} + 2 a = - 2

Move

2

to the left side

5 a^{2} + 2 a + 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

Simplify

2^{2} - 4 \cdot 5 \cdot 2 : 6 i

a_{1, 2} = \frac{- 2 \pm 6 i}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- 2 + 6 i}{2 \cdot 5}, a_{2} = \frac{- 2 - 6 i}{2 \cdot 5}

a = \frac{- 2 + 6 i}{2 \cdot 5} : - \frac{1}{5} + i \frac{3}{5}

a = \frac{- 2 - 6 i}{2 \cdot 5} : - \frac{1}{5} - i \frac{3}{5}

The solutions to the quadratic equation are:

a = - \frac{1}{5} + i \frac{3}{5}, a = - \frac{1}{5} - i \frac{3}{5}

x, 4 x^{2} - 3 x y - 18 = 0

x^{2} + 3 x + 3 = - 1

y = x^{2} + 3, x

2 x^{2} = 24 - 8 x

x = 0.55 \cdot (22 - 1.71 x - 4)^{2}

What are the solutions to the equation 5a^2+4a=-2+2a ?
The solutions to the equation 5a^2+4a=-2+2a are a=-1/5+i 3/5 ,a=-1/5-i 3/5
Find the zeros of 5a^2+4a=-2+2a
The zeros of 5a^2+4a=-2+2a are a=-1/5+i 3/5 ,a=-1/5-i 3/5