What are the solutions to the equation (4x+9)^2=64 ?

The solutions to the equation (4x+9)^2=64 are x=-1/4 ,x=-17/4

Find the zeros of (4x+9)^2=64

The zeros of (4x+9)^2=64 are x=-1/4 ,x=-17/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(4 x + 9)^{2} = 64

x = - \frac{1}{4}, x = - \frac{17}{4}

Decimal Notation

x = - 0.25, x = - 4.25

Solution steps

(4 x + 9)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 9 = 64 : x = - \frac{1}{4}

Solve

4 x + 9 = - 64 : x = - \frac{17}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - \frac{17}{4}

x, f = x^{2} - 2 x y - y^{2}

(x + 9)^{2} = (x + 1)^{2} + x^{2}

x^{2} + 11 x + 24 = 0

80000 = 100 - 6.25 (x - 9)^{2}

t (t + 1) = 3 t^{2} + 1

What are the solutions to the equation (4x+9)^2=64 ?
The solutions to the equation (4x+9)^2=64 are x=-1/4 ,x=-17/4
Find the zeros of (4x+9)^2=64
The zeros of (4x+9)^2=64 are x=-1/4 ,x=-17/4