What are the solutions to the equation 5w^2+13w=-6 ?

The solutions to the equation 5w^2+13w=-6 are w=-3/5 ,w=-2

Find the zeros of 5w^2+13w=-6

The zeros of 5w^2+13w=-6 are w=-3/5 ,w=-2

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5 w^{2} + 13 w = - 6

w = - \frac{3}{5}, w = - 2

Decimal Notation

w = - 0.6, w = - 2

Solution steps

5 w^{2} + 13 w = - 6

Move

6

to the left side

5 w^{2} + 13 w + 6 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

1 3^{2} - 4 \cdot 5 \cdot 6 = 7

w_{1, 2} = \frac{- 13 \pm 7}{2 \cdot 5}

Separate the solutions

w_{1} = \frac{- 13 + 7}{2 \cdot 5}, w_{2} = \frac{- 13 - 7}{2 \cdot 5}

w = \frac{- 13 + 7}{2 \cdot 5} : - \frac{3}{5}

w = \frac{- 13 - 7}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

w = - \frac{3}{5}, w = - 2

x^{2} + 4 x + 5 = 0

0 + \frac{x ^{2}}{25} = 400

z (3 z + 2) = 8

(x - \frac{1}{6})^{2} - \frac{1}{7} (x + 7) (x - 7) = (x + \frac{1}{6}) - \frac{1}{7} x^{2}

N (t) = t^{2} + 2 t + 150

What are the solutions to the equation 5w^2+13w=-6 ?
The solutions to the equation 5w^2+13w=-6 are w=-3/5 ,w=-2
Find the zeros of 5w^2+13w=-6
The zeros of 5w^2+13w=-6 are w=-3/5 ,w=-2