What are the solutions to the equation a^2-8a-32=0 ?

The solutions to the equation a^2-8a-32=0 are a=4(1+sqrt(3)),a=4(1-sqrt(3))

Find the zeros of a^2-8a-32=0

The zeros of a^2-8a-32=0 are a=4(1+sqrt(3)),a=4(1-sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

a^{2} - 8 a - 32 = 0

a = 4 (1 + 3), a = 4 (1 - 3)

Decimal Notation

a = 10.92820 \dots, a = - 2.92820 \dots

Solution steps

a^{2} - 8 a - 32 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 32) = 83

a_{1, 2} = \frac{- ( - 8 ) \pm 8 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 8 ) + 8 3}{2 \cdot 1}, a_{2} = \frac{- ( - 8 ) - 8 3}{2 \cdot 1}

a = \frac{- ( - 8 ) + 8 3}{2 \cdot 1} : 4 (1 + 3)

a = \frac{- ( - 8 ) - 8 3}{2 \cdot 1} : 4 (1 - 3)

The solutions to the quadratic equation are:

a = 4 (1 + 3), a = 4 (1 - 3)

2 x^{2} + 4 = x^{2} + 8

x^{2} + 4 x + 2 = 0

u^{2} + 7 u + 10 = 0

\frac{5}{3} p + \frac{2}{3} = 5 + \frac{p}{2} p

6 x^{2} + 3 x + 3 = 0

What are the solutions to the equation a^2-8a-32=0 ?
The solutions to the equation a^2-8a-32=0 are a=4(1+sqrt(3)),a=4(1-sqrt(3))
Find the zeros of a^2-8a-32=0
The zeros of a^2-8a-32=0 are a=4(1+sqrt(3)),a=4(1-sqrt(3))