What are the solutions to the equation 3x^2-18x+6=0 ?

The solutions to the equation 3x^2-18x+6=0 are x=3+sqrt(7),x=3-sqrt(7)

Find the zeros of 3x^2-18x+6=0

The zeros of 3x^2-18x+6=0 are x=3+sqrt(7),x=3-sqrt(7)

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3 x^{2} - 18 x + 6 = 0

x = 3 + 7, x = 3 - 7

Decimal Notation

x = 5.64575 \dots, x = 0.35424 \dots

Solution steps

3 x^{2} - 18 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 6 = 67

x_{1, 2} = \frac{- ( - 18 ) \pm 6 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 7}{2 \cdot 3}, x_{2} = \frac{- ( - 18 ) - 6 7}{2 \cdot 3}

x = \frac{- ( - 18 ) + 6 7}{2 \cdot 3} : 3 + 7

x = \frac{- ( - 18 ) - 6 7}{2 \cdot 3} : 3 - 7

The solutions to the quadratic equation are:

x = 3 + 7, x = 3 - 7

1. 9^{2} + a^{2} = 2. 4^{2}

x, x^{2} + 4 y^{2} - z^{2} = - 9

x^{2} - 14 x - 51 = 0

\frac{x ^{2}}{9} - 1 = 15

- 3 x^{2} - 6 x - 1 = 0

What are the solutions to the equation 3x^2-18x+6=0 ?
The solutions to the equation 3x^2-18x+6=0 are x=3+sqrt(7),x=3-sqrt(7)
Find the zeros of 3x^2-18x+6=0
The zeros of 3x^2-18x+6=0 are x=3+sqrt(7),x=3-sqrt(7)