What are the solutions to the equation factor t^2-5t+6=0 ?

The solutions to the equation factor t^2-5t+6=0 are t=2,t=3

Find the zeros of factor t^2-5t+6=0

The zeros of factor t^2-5t+6=0 are t=2,t=3

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t^{2} - 5 t + 6 = 0

t = 2, t = 3

Solution steps

t^{2} - 5 t + 6 = 0

Factor

t^{2} - 5 t + 6 : (t - 2) (t - 3)

(t - 2) (t - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t - 2 = 0 or t - 3 = 0

Solve

t - 2 = 0 : t = 2

Solve

t - 3 = 0 : t = 3

The solutions to the quadratic equation are:

t = 2, t = 3

4 x^{2} - 12 x + 4 = 0

x^{2} - 6 x - 5

- 2 y^{2} = 1 - 3 y^{2}

\frac{1}{2} \cdot 2 \cdot 5^{2} + 2 \cdot 9.8 \cdot 20 = \frac{1}{2} \cdot x^{2}

3 x = x^{2} + 5

What are the solutions to the equation factor t^2-5t+6=0 ?
The solutions to the equation factor t^2-5t+6=0 are t=2,t=3
Find the zeros of factor t^2-5t+6=0
The zeros of factor t^2-5t+6=0 are t=2,t=3