What are the solutions to the equation x^2+4x=6 ?

The solutions to the equation x^2+4x=6 are x=-2+sqrt(10),x=-2-sqrt(10)

Find the zeros of x^2+4x=6

The zeros of x^2+4x=6 are x=-2+sqrt(10),x=-2-sqrt(10)

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x^{2} + 4 x = 6

x = - 2 + 10, x = - 2 - 10

Decimal Notation

x = 1.16227 \dots, x = - 5.16227 \dots

Solution steps

x^{2} + 4 x = 6

Move

6

to the left side

x^{2} + 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 6) = 210

x_{1, 2} = \frac{- 4 \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 10}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 10}{2 \cdot 1}

x = \frac{- 4 + 2 10}{2 \cdot 1} : - 2 + 10

x = \frac{- 4 - 2 10}{2 \cdot 1} : - 2 - 10

The solutions to the quadratic equation are:

x = - 2 + 10, x = - 2 - 10

(k^{\frac{3}{2}})^{\frac{1}{2}}

\frac{a}{6} = 5

- 5 \cdot 2

\frac{- 1 + 2 i}{i}

3 x^{2} + 4 x + 1 = 0

What are the solutions to the equation x^2+4x=6 ?
The solutions to the equation x^2+4x=6 are x=-2+sqrt(10),x=-2-sqrt(10)
Find the zeros of x^2+4x=6
The zeros of x^2+4x=6 are x=-2+sqrt(10),x=-2-sqrt(10)