What are the solutions to the equation 1/20 x^2+x+50=0 ?

The solutions to the equation 1/20 x^2+x+50=0 are x=-10+30i,x=-10-30i

Find the zeros of 1/20 x^2+x+50=0

The zeros of 1/20 x^2+x+50=0 are x=-10+30i,x=-10-30i

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\frac{1}{20} x^{2} + x + 50 = 0

x = - 10 + 30 i, x = - 10 - 30 i

Solution steps

\frac{1}{20} x^{2} + x + 50 = 0

Multiply both sides by

20

x^{2} + 20 x + 1000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 1000}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 1000 : 60 i

x_{1, 2} = \frac{- 20 \pm 60 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 60 i}{2 \cdot 1}, x_{2} = \frac{- 20 - 60 i}{2 \cdot 1}

x = \frac{- 20 + 60 i}{2 \cdot 1} : - 10 + 30 i

x = \frac{- 20 - 60 i}{2 \cdot 1} : - 10 - 30 i

The solutions to the quadratic equation are:

x = - 10 + 30 i, x = - 10 - 30 i

4 x^{2} = 21 x + 18

0.15 x^{2} + 0.1485 x - 0.2 = 0

4 a^{2} = 1

a, f (a^{2}) = f^{- 1} (a + 2)

X^{2} + 5 X - 6 = 0

What are the solutions to the equation 1/20 x^2+x+50=0 ?
The solutions to the equation 1/20 x^2+x+50=0 are x=-10+30i,x=-10-30i
Find the zeros of 1/20 x^2+x+50=0
The zeros of 1/20 x^2+x+50=0 are x=-10+30i,x=-10-30i