What are the solutions to the equation (5p+1)^2=12 ?

The solutions to the equation (5p+1)^2=12 are p=(2sqrt(3)-1)/5 ,p=(-2sqrt(3)-1)/5

Find the zeros of (5p+1)^2=12

The zeros of (5p+1)^2=12 are p=(2sqrt(3)-1)/5 ,p=(-2sqrt(3)-1)/5

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(5 p + 1)^{2} = 12

p = \frac{2 3 - 1}{5}, p = \frac{- 2 3 - 1}{5}

Decimal Notation

p = 0.49282 \dots, p = - 0.89282 \dots

Solution steps

(5 p + 1)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 p + 1 = 12 : p = \frac{2 3 - 1}{5}

Solve

5 p + 1 = - 12 : p = \frac{- 2 3 - 1}{5}

The solutions to the quadratic equation are:

p = \frac{2 3 - 1}{5}, p = \frac{- 2 3 - 1}{5}

81 x^{2} = 169

r^{2} - 3 r = 0

9 a^{2} = 81

- x^{2} - 2 x + 4 = 2 - 2 x

2 x^{2} - 4 x + 8 = 5 x^{2} + 2 x - 5

What are the solutions to the equation (5p+1)^2=12 ?
The solutions to the equation (5p+1)^2=12 are p=(2sqrt(3)-1)/5 ,p=(-2sqrt(3)-1)/5
Find the zeros of (5p+1)^2=12
The zeros of (5p+1)^2=12 are p=(2sqrt(3)-1)/5 ,p=(-2sqrt(3)-1)/5