What are the solutions to the equation solvefor x,9x^2+12x+4=6 ?

The solutions to the equation solvefor x,9x^2+12x+4=6 are x=(-2+sqrt(6))/3 ,x=-(2+sqrt(6))/3

Find the zeros of solvefor x,9x^2+12x+4=6

The zeros of solvefor x,9x^2+12x+4=6 are x=(-2+sqrt(6))/3 ,x=-(2+sqrt(6))/3

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x, 9 x^{2} + 12 x + 4 = 6

x = \frac{- 2 + 6}{3}, x = - \frac{2 + 6}{3}

Decimal Notation

x = 0.14982 \dots, x = - 1.48316 \dots

Solution steps

9 x^{2} + 12 x + 4 = 6

Move

6

to the left side

9 x^{2} + 12 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

1 2^{2} - 4 \cdot 9 (- 2) = 66

x_{1, 2} = \frac{- 12 \pm 6 6}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 12 + 6 6}{2 \cdot 9}, x_{2} = \frac{- 12 - 6 6}{2 \cdot 9}

x = \frac{- 12 + 6 6}{2 \cdot 9} : \frac{- 2 + 6}{3}

x = \frac{- 12 - 6 6}{2 \cdot 9} : - \frac{2 + 6}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 6}{3}, x = - \frac{2 + 6}{3}

20 = 50 t - 5 t^{2}

y, x^{2} - x y + y^{2} = 7

x^{2} = 1.6 x

x^{2} = 1.3 x

x^{2} + 3 - 2 x = 0

What are the solutions to the equation solvefor x,9x^2+12x+4=6 ?
The solutions to the equation solvefor x,9x^2+12x+4=6 are x=(-2+sqrt(6))/3 ,x=-(2+sqrt(6))/3
Find the zeros of solvefor x,9x^2+12x+4=6
The zeros of solvefor x,9x^2+12x+4=6 are x=(-2+sqrt(6))/3 ,x=-(2+sqrt(6))/3