What are the solutions to the equation 4x^2-16x+16=4x ?

The solutions to the equation 4x^2-16x+16=4x are x=4,x=1

Find the zeros of 4x^2-16x+16=4x

The zeros of 4x^2-16x+16=4x are x=4,x=1

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4 x^{2} - 16 x + 16 = 4 x

x = 4, x = 1

Solution steps

4 x^{2} - 16 x + 16 = 4 x

Move

4 x

to the left side

4 x^{2} - 20 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 16}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 16 = 12

x_{1, 2} = \frac{- ( - 20 ) \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 12}{2 \cdot 4}, x_{2} = \frac{- ( - 20 ) - 12}{2 \cdot 4}

x = \frac{- ( - 20 ) + 12}{2 \cdot 4} : 4

x = \frac{- ( - 20 ) - 12}{2 \cdot 4} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

x^{2} + 6 - 5 x = 0

(x - 1)^{2} - 36 = 0

(x - 1)^{2} - 36 = 1

4 m^{2} + 6 m = 6 m + 36

(x) = 7 x^{2} - x + 1

What are the solutions to the equation 4x^2-16x+16=4x ?
The solutions to the equation 4x^2-16x+16=4x are x=4,x=1
Find the zeros of 4x^2-16x+16=4x
The zeros of 4x^2-16x+16=4x are x=4,x=1