What are the solutions to the equation 14=(2x-3)^2-2 ?

The solutions to the equation 14=(2x-3)^2-2 are x= 7/2 ,x=-1/2

Find the zeros of 14=(2x-3)^2-2

The zeros of 14=(2x-3)^2-2 are x= 7/2 ,x=-1/2

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14 = (2 x - 3)^{2} - 2

x = \frac{7}{2}, x = - \frac{1}{2}

Decimal Notation

x = 3.5, x = - 0.5

Solution steps

14 = (2 x - 3)^{2} - 2

Switch sides

(2 x - 3)^{2} - 2 = 14

Move

2

to the right side

(2 x - 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 16 : x = \frac{7}{2}

Solve

2 x - 3 = - 16 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - \frac{1}{2}

x^{2} - 0.3 x - 0.7 = 0

2 r^{2} - r - 4 = 0

x, 12 x^{2} - 288 x + 1296 = 0

3 (x - 5)^{2} - 12 = 0

3 x^{2} + 2 x - 1 = 0

What are the solutions to the equation 14=(2x-3)^2-2 ?
The solutions to the equation 14=(2x-3)^2-2 are x= 7/2 ,x=-1/2
Find the zeros of 14=(2x-3)^2-2
The zeros of 14=(2x-3)^2-2 are x= 7/2 ,x=-1/2