What are the solutions to the equation ((15c^2-8c))/3 =4 ?

The solutions to the equation ((15c^2-8c))/3 =4 are c= 6/5 ,c=-2/3

Find the zeros of ((15c^2-8c))/3 =4

The zeros of ((15c^2-8c))/3 =4 are c= 6/5 ,c=-2/3

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\frac{( 15 c ^{2} - 8 c )}{3} = 4

c = \frac{6}{5}, c = - \frac{2}{3}

Decimal Notation

c = 1.2, c = - 0.66666 \dots

Solution steps

\frac{( 15 c ^{2} - 8 c )}{3} = 4

Multiply both sides by

3

15 c^{2} - 8 c = 12

Move

12

to the left side

15 c^{2} - 8 c - 12 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 15 ( - 12 )}{2 \cdot 15}

(- 8)^{2} - 4 \cdot 15 (- 12) = 28

c_{1, 2} = \frac{- ( - 8 ) \pm 28}{2 \cdot 15}

Separate the solutions

c_{1} = \frac{- ( - 8 ) + 28}{2 \cdot 15}, c_{2} = \frac{- ( - 8 ) - 28}{2 \cdot 15}

c = \frac{- ( - 8 ) + 28}{2 \cdot 15} : \frac{6}{5}

c = \frac{- ( - 8 ) - 28}{2 \cdot 15} : - \frac{2}{3}

The solutions to the quadratic equation are:

c = \frac{6}{5}, c = - \frac{2}{3}

x^{2} = x (4 - x)

5 x^{2} - 8 x + 12 = 3 x + 10

(a + 4)^{2} = 2 a (5 a - 1) - 7 (a - 2)

4 x^{2} - 3 x + c = 0

5 b^{2} - 25 = 0

What are the solutions to the equation ((15c^2-8c))/3 =4 ?
The solutions to the equation ((15c^2-8c))/3 =4 are c= 6/5 ,c=-2/3
Find the zeros of ((15c^2-8c))/3 =4
The zeros of ((15c^2-8c))/3 =4 are c= 6/5 ,c=-2/3