What are the solutions to the equation 250=-0.01x^2+50x-300 ?

The solutions to the equation 250=-0.01x^2+50x-300 are x=50(50-sqrt(2478)),x=50(50+sqrt(2478))

Find the zeros of 250=-0.01x^2+50x-300

The zeros of 250=-0.01x^2+50x-300 are x=50(50-sqrt(2478)),x=50(50+sqrt(2478))

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250 = - 0.01 x^{2} + 50 x - 300

x = 50 (50 - 2478), x = 50 (50 + 2478)

Decimal Notation

x = 11.02430 \dots, x = 4988.97569 \dots

Solution steps

250 = - 0.01 x^{2} + 50 x - 300

Multiply both sides by

100

25000 = - x^{2} + 5000 x - 30000

Switch sides

- x^{2} + 5000 x - 30000 = 25000

Move

25000

to the left side

- x^{2} + 5000 x - 55000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5000 \pm 500 0 ^{2} - 4 ( - 1 ) ( - 55000 )}{2 ( - 1 )}

500 0^{2} - 4 (- 1) (- 55000) = 1002478

x_{1, 2} = \frac{- 5000 \pm 100 2478}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5000 + 100 2478}{2 ( - 1 )}, x_{2} = \frac{- 5000 - 100 2478}{2 ( - 1 )}

x = \frac{- 5000 + 100 2478}{2 ( - 1 )} : 50 (50 - 2478)

x = \frac{- 5000 - 100 2478}{2 ( - 1 )} : 50 (50 + 2478)

The solutions to the quadratic equation are:

x = 50 (50 - 2478), x = 50 (50 + 2478)

3 x^{2} + 22 x + 15 = 0

x^{2} - 12 x + 9 = 2 x - 4

- 13 m - m^{2} = 0

25 x^{2} - 50 x - 25 = 0

5 x^{2} - 8 x - 30 = 0

What are the solutions to the equation 250=-0.01x^2+50x-300 ?
The solutions to the equation 250=-0.01x^2+50x-300 are x=50(50-sqrt(2478)),x=50(50+sqrt(2478))
Find the zeros of 250=-0.01x^2+50x-300
The zeros of 250=-0.01x^2+50x-300 are x=50(50-sqrt(2478)),x=50(50+sqrt(2478))