What are the solutions to the equation 3x^2-16x+10=0 ?

The solutions to the equation 3x^2-16x+10=0 are x=(8+sqrt(34))/3 ,x=(8-sqrt(34))/3

Find the zeros of 3x^2-16x+10=0

The zeros of 3x^2-16x+10=0 are x=(8+sqrt(34))/3 ,x=(8-sqrt(34))/3

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3 x^{2} - 16 x + 10 = 0

x = \frac{8 + 34}{3}, x = \frac{8 - 34}{3}

Decimal Notation

x = 4.61031 \dots, x = 0.72301 \dots

Solution steps

3 x^{2} - 16 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 \cdot 10 = 234

x_{1, 2} = \frac{- ( - 16 ) \pm 2 34}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 34}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 2 34}{2 \cdot 3}

x = \frac{- ( - 16 ) + 2 34}{2 \cdot 3} : \frac{8 + 34}{3}

x = \frac{- ( - 16 ) - 2 34}{2 \cdot 3} : \frac{8 - 34}{3}

The solutions to the quadratic equation are:

x = \frac{8 + 34}{3}, x = \frac{8 - 34}{3}

x^{2} - 9 x - 8 = 0

A, E = \frac{1}{2} k A^{2}

5 x^{2} - 2 = 6

x \cdot (x + 1) = 20

4 x^{2} = 5 (4 x - 5)

What are the solutions to the equation 3x^2-16x+10=0 ?
The solutions to the equation 3x^2-16x+10=0 are x=(8+sqrt(34))/3 ,x=(8-sqrt(34))/3
Find the zeros of 3x^2-16x+10=0
The zeros of 3x^2-16x+10=0 are x=(8+sqrt(34))/3 ,x=(8-sqrt(34))/3