What are the solutions to the equation 0=-16t^2+16t+370 ?

The solutions to the equation 0=-16t^2+16t+370 are t=-(-2+sqrt(374))/4 ,t=(2+sqrt(374))/4

Find the zeros of 0=-16t^2+16t+370

The zeros of 0=-16t^2+16t+370 are t=-(-2+sqrt(374))/4 ,t=(2+sqrt(374))/4

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0 = - 16 t^{2} + 16 t + 370

t = - \frac{- 2 + 374}{4}, t = \frac{2 + 374}{4}

Decimal Notation

t = - 4.33476 \dots, t = 5.33476 \dots

Solution steps

0 = - 16 t^{2} + 16 t + 370

Switch sides

- 16 t^{2} + 16 t + 370 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 16 ) \cdot 370}{2 ( - 16 )}

1 6^{2} - 4 (- 16) \cdot 370 = 8374

t_{1, 2} = \frac{- 16 \pm 8 374}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 16 + 8 374}{2 ( - 16 )}, t_{2} = \frac{- 16 - 8 374}{2 ( - 16 )}

t = \frac{- 16 + 8 374}{2 ( - 16 )} : - \frac{- 2 + 374}{4}

t = \frac{- 16 - 8 374}{2 ( - 16 )} : \frac{2 + 374}{4}

The solutions to the quadratic equation are:

t = - \frac{- 2 + 374}{4}, t = \frac{2 + 374}{4}

4 = 3 + (y - 5)^{2}

0 = - 16 t^{2} + 16 t + 320

8 - p^{2} = p^{2}

x - 1 = x^{2} - 1

x^{2} + 160 = 0

What are the solutions to the equation 0=-16t^2+16t+370 ?
The solutions to the equation 0=-16t^2+16t+370 are t=-(-2+sqrt(374))/4 ,t=(2+sqrt(374))/4
Find the zeros of 0=-16t^2+16t+370
The zeros of 0=-16t^2+16t+370 are t=-(-2+sqrt(374))/4 ,t=(2+sqrt(374))/4