What are the solutions to the equation 2x^2-8x=12 ?

The solutions to the equation 2x^2-8x=12 are x=2+sqrt(10),x=2-sqrt(10)

Find the zeros of 2x^2-8x=12

The zeros of 2x^2-8x=12 are x=2+sqrt(10),x=2-sqrt(10)

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2 x^{2} - 8 x = 12

x = 2 + 10, x = 2 - 10

Decimal Notation

x = 5.16227 \dots, x = - 1.16227 \dots

Solution steps

2 x^{2} - 8 x = 12

Move

12

to the left side

2 x^{2} - 8 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 12) = 410

x_{1, 2} = \frac{- ( - 8 ) \pm 4 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 10}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 4 10}{2 \cdot 2}

x = \frac{- ( - 8 ) + 4 10}{2 \cdot 2} : 2 + 10

x = \frac{- ( - 8 ) - 4 10}{2 \cdot 2} : 2 - 10

The solutions to the quadratic equation are:

x = 2 + 10, x = 2 - 10

4 x = 60

- 161

0.2 5^{- 2}

12 + 27

64 m^{2} - 9 y^{2}

What are the solutions to the equation 2x^2-8x=12 ?
The solutions to the equation 2x^2-8x=12 are x=2+sqrt(10),x=2-sqrt(10)
Find the zeros of 2x^2-8x=12
The zeros of 2x^2-8x=12 are x=2+sqrt(10),x=2-sqrt(10)