What are the solutions to the equation 0=3x^2+18x+27 ?

The solutions to the equation 0=3x^2+18x+27 are x=-3

Find the zeros of 0=3x^2+18x+27

The zeros of 0=3x^2+18x+27 are x=-3

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0 = 3 x^{2} + 18 x + 27

x = - 3

Solution steps

0 = 3 x^{2} + 18 x + 27

Switch sides

3 x^{2} + 18 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 \cdot 27}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 \cdot 27 = 0

x_{1, 2} = \frac{- 18 \pm 0}{2 \cdot 3}

x = \frac{- 18}{2 \cdot 3}

\frac{- 18}{2 \cdot 3} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

x (7 x - 12) = 0

(5) = - 0.12 x^{2} - 1.2 x + 445

x^{2} + 10 x - 18 = 0

(3 x - 2)^{2} = (2 x + 1) (2 x - 1) - 2

4 x^{2} + 3 x - 4 = 0

What are the solutions to the equation 0=3x^2+18x+27 ?
The solutions to the equation 0=3x^2+18x+27 are x=-3
Find the zeros of 0=3x^2+18x+27
The zeros of 0=3x^2+18x+27 are x=-3