What are the solutions to the equation c*c-c=6 ?

The solutions to the equation c*c-c=6 are c=3,c=-2

Find the zeros of c*c-c=6

The zeros of c*c-c=6 are c=3,c=-2

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c \cdot c - c = 6

c = 3, c = - 2

Solution steps

cc - c = 6

Expand

cc - c : c^{2} - c

c^{2} - c = 6

Move

6

to the left side

c^{2} - c - 6 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

c_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, c_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

c = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

c = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

c = 3, c = - 2

- 2 m^{2} + 2 m - 1 = 0

4 x^{2} - 6 x + 11 = 0

4 y^{2} + 19 y + 12 = 0

2 x - 1 = x^{2} - 2 x + 1

(x + a)^{2} = 0

What are the solutions to the equation c*c-c=6 ?
The solutions to the equation c*c-c=6 are c=3,c=-2
Find the zeros of c*c-c=6
The zeros of c*c-c=6 are c=3,c=-2