What are the solutions to the equation x^2-12=7x ?

The solutions to the equation x^2-12=7x are x=(7+sqrt(97))/2 ,x=(7-sqrt(97))/2

Find the zeros of x^2-12=7x

The zeros of x^2-12=7x are x=(7+sqrt(97))/2 ,x=(7-sqrt(97))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 12 = 7 x

x = \frac{7 + 97}{2}, x = \frac{7 - 97}{2}

Decimal Notation

x = 8.42442 \dots, x = - 1.42442 \dots

Solution steps

x^{2} - 12 = 7 x

Move

7 x

to the left side

x^{2} - 12 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 7 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 12) = 97

x_{1, 2} = \frac{- ( - 7 ) \pm 97}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 97}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 97}{2 \cdot 1}

x = \frac{- ( - 7 ) + 97}{2 \cdot 1} : \frac{7 + 97}{2}

x = \frac{- ( - 7 ) - 97}{2 \cdot 1} : \frac{7 - 97}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 97}{2}, x = \frac{7 - 97}{2}

3 x^{2} + x - \frac{1}{2} = 0

x, x^{2} y - 9 y - x^{2} + 3 = 0

37500 X^{2} + 2117.1 X + 8177.4 = 0

k (- 3) = 2 x^{2} - 5 x + 3

112 + 96 t - 16 t^{2} = 112

What are the solutions to the equation x^2-12=7x ?
The solutions to the equation x^2-12=7x are x=(7+sqrt(97))/2 ,x=(7-sqrt(97))/2
Find the zeros of x^2-12=7x
The zeros of x^2-12=7x are x=(7+sqrt(97))/2 ,x=(7-sqrt(97))/2