What are the solutions to the equation x+(x^2+4)/5 =2 ?

The solutions to the equation x+(x^2+4)/5 =2 are x=1,x=-6

Find the zeros of x+(x^2+4)/5 =2

The zeros of x+(x^2+4)/5 =2 are x=1,x=-6

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x + \frac{x ^{2} + 4}{5} = 2

x = 1, x = - 6

Solution steps

x + \frac{x ^{2} + 4}{5} = 2

Multiply both sides by

5

5 x + x^{2} + 4 = 10

Move

10

to the left side

x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 1}, x_{2} = \frac{- 5 - 7}{2 \cdot 1}

x = \frac{- 5 + 7}{2 \cdot 1} : 1

x = \frac{- 5 - 7}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 1, x = - 6

x^{2} + 22 x - 4 = 0

- 25 x^{2} + 4 x = 0

a, 14 (a^{2} + b^{2} + c^{2}) = (a + 2 b + 3 c)^{2}

x^{2} - 8 x + 25

x^{2} - 8 x + 16

What are the solutions to the equation x+(x^2+4)/5 =2 ?
The solutions to the equation x+(x^2+4)/5 =2 are x=1,x=-6
Find the zeros of x+(x^2+4)/5 =2
The zeros of x+(x^2+4)/5 =2 are x=1,x=-6