What are the solutions to the equation x(x-16)+63=0 ?

The solutions to the equation x(x-16)+63=0 are x=9,x=7

Find the zeros of x(x-16)+63=0

The zeros of x(x-16)+63=0 are x=9,x=7

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x (x - 16) + 63 = 0

x = 9, x = 7

Solution steps

x (x - 16) + 63 = 0

Expand

x (x - 16) + 63 : x^{2} - 16 x + 63

x^{2} - 16 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 63}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 63 = 2

x_{1, 2} = \frac{- ( - 16 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2}{2 \cdot 1} : 9

x = \frac{- ( - 16 ) - 2}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

x = 9, x = 7

q, p = 2 q^{2}

d, a \cdot [a + d] \cdot [a + 2 d] = 16

7 m^{2} + 2 = 170

x^{2} + 89 = - 20 x

(3 x + 2) (2 x + 3) = (x - 3) (2 x - 4)

What are the solutions to the equation x(x-16)+63=0 ?
The solutions to the equation x(x-16)+63=0 are x=9,x=7
Find the zeros of x(x-16)+63=0
The zeros of x(x-16)+63=0 are x=9,x=7