What are the solutions to the equation 4+z^2=0 ?

The solutions to the equation 4+z^2=0 are z=2i,z=-2i

Find the zeros of 4+z^2=0

The zeros of 4+z^2=0 are z=2i,z=-2i

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4 + z^{2} = 0

z = 2 i, z = - 2 i

Solution steps

4 + z^{2} = 0

Move

4

to the right side

z^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = - 4, z = - - 4

- 4 = 2 i

- - 4 = - 2 i

z = 2 i, z = - 2 i

y^{2} + 7 y = 18

- x^{2} + 5 x - 5 = 0

x, x^{2} + m x + 3 = 0

m^{2} - 5 m = 84

r (r - 1) + \frac{1}{2} r = 0

What are the solutions to the equation 4+z^2=0 ?
The solutions to the equation 4+z^2=0 are z=2i,z=-2i
Find the zeros of 4+z^2=0
The zeros of 4+z^2=0 are z=2i,z=-2i