What are the solutions to the equation 665x^2+20x-150=0 ?

The solutions to the equation 665x^2+20x-150=0 are x=(-2+sqrt(3994))/(133),x=-(2+sqrt(3994))/(133)

Find the zeros of 665x^2+20x-150=0

The zeros of 665x^2+20x-150=0 are x=(-2+sqrt(3994))/(133),x=-(2+sqrt(3994))/(133)

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665 x^{2} + 20 x - 150 = 0

x = \frac{- 2 + 3994}{133}, x = - \frac{2 + 3994}{133}

Decimal Notation

x = 0.46013 \dots, x = - 0.49021 \dots

Solution steps

665 x^{2} + 20 x - 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 665 ( - 150 )}{2 \cdot 665}

2 0^{2} - 4 \cdot 665 (- 150) = 103994

x_{1, 2} = \frac{- 20 \pm 10 3994}{2 \cdot 665}

Separate the solutions

x_{1} = \frac{- 20 + 10 3994}{2 \cdot 665}, x_{2} = \frac{- 20 - 10 3994}{2 \cdot 665}

x = \frac{- 20 + 10 3994}{2 \cdot 665} : \frac{- 2 + 3994}{133}

x = \frac{- 20 - 10 3994}{2 \cdot 665} : - \frac{2 + 3994}{133}

The solutions to the quadratic equation are:

x = \frac{- 2 + 3994}{133}, x = - \frac{2 + 3994}{133}

\frac{x ^{2} + 2}{2} = \frac{7 x - 5}{3}

a, \frac{1 ( a + 7 ) ( ab )}{2} = c (c + d) d

x, x^{2} + y^{2} + z^{2} = 13

x, x^{2} + y^{2} + z^{2} = 10

(x) = 4 x^{2} - 9 x + 16

What are the solutions to the equation 665x^2+20x-150=0 ?
The solutions to the equation 665x^2+20x-150=0 are x=(-2+sqrt(3994))/(133),x=-(2+sqrt(3994))/(133)
Find the zeros of 665x^2+20x-150=0
The zeros of 665x^2+20x-150=0 are x=(-2+sqrt(3994))/(133),x=-(2+sqrt(3994))/(133)