What are the solutions to the equation 2m^2+8m+8=0 ?

The solutions to the equation 2m^2+8m+8=0 are m=-2

Find the zeros of 2m^2+8m+8=0

The zeros of 2m^2+8m+8=0 are m=-2

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2 m^{2} + 8 m + 8 = 0

m = - 2

Solution steps

2 m^{2} + 8 m + 8 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 8 = 0

m_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 2}

m = \frac{- 8}{2 \cdot 2}

\frac{- 8}{2 \cdot 2} = - 2

m = - 2

The solution to the quadratic equation is:

m = - 2

- 5 t^{2} + 9 t + 3 = 0

2 x^{2} + 20 x - 8 = 0

321.0069 x^{2} - 5130.1778 x + 14682.6031 = 0

x (5 x - 2) = 24

x^{2} - 18 x + 4 = 0

What are the solutions to the equation 2m^2+8m+8=0 ?
The solutions to the equation 2m^2+8m+8=0 are m=-2
Find the zeros of 2m^2+8m+8=0
The zeros of 2m^2+8m+8=0 are m=-2