What are the solutions to the equation (3x+1)(x+7)=100 ?

The solutions to the equation (3x+1)(x+7)=100 are x=3,x=-31/3

Find the zeros of (3x+1)(x+7)=100

The zeros of (3x+1)(x+7)=100 are x=3,x=-31/3

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(3 x + 1) (x + 7) = 100

x = 3, x = - \frac{31}{3}

Decimal Notation

x = 3, x = - 10.33333 \dots

Solution steps

(3 x + 1) (x + 7) = 100

Expand

(3 x + 1) (x + 7) : 3 x^{2} + 22 x + 7

3 x^{2} + 22 x + 7 = 100

Move

100

to the left side

3 x^{2} + 22 x - 93 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 3 ( - 93 )}{2 \cdot 3}

2 2^{2} - 4 \cdot 3 (- 93) = 40

x_{1, 2} = \frac{- 22 \pm 40}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 22 + 40}{2 \cdot 3}, x_{2} = \frac{- 22 - 40}{2 \cdot 3}

x = \frac{- 22 + 40}{2 \cdot 3} : 3

x = \frac{- 22 - 40}{2 \cdot 3} : - \frac{31}{3}

The solutions to the quadratic equation are:

x = 3, x = - \frac{31}{3}

81 = 3 w^{2}

a^{2} + 2 0^{2} = 2 5^{2}

2 a^{2} + 11 a + 10 = 0

3 x^{2} + 64 = \frac{2 x ^{2}}{2}

3 w^{2} + 12 w - 15 = 0

What are the solutions to the equation (3x+1)(x+7)=100 ?
The solutions to the equation (3x+1)(x+7)=100 are x=3,x=-31/3
Find the zeros of (3x+1)(x+7)=100
The zeros of (3x+1)(x+7)=100 are x=3,x=-31/3