What is (3^{-4}x^0)/(y^{-8)} ?

The solution to (3^{-4}x^0)/(y^{-8)} is (y^8)/(81)

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simplify (3^{-4}x^0)/(y^{-8)}

simplify

\frac{3 ^{- 4} x ^{0}}{y ^{- 8}}

\frac{y ^{8}}{81}

Solution steps

\frac{3 ^{- 4} x ^{0}}{y ^{- 8}}

Simplify

3^{- 4} x^{0} : \frac{1}{81}

= \frac{\frac{1}{81}}{y ^{- 8}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{81 y ^{- 8}}

Simplify

81 y^{- 8} : \frac{81}{y ^{8}}

= \frac{1}{\frac{81}{y ^{8}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{8}}{81}

(x^{\frac{2}{3}})^{\frac{3}{2}}

\frac{y ^{- 4}}{y ^{- 7}}

3 x^{2} + x - 10 = 0

\frac{3}{1} \cdot \frac{2}{3}

s^{2} - 5 s + 6

What is (3^{-4}x^0)/(y^{-8)} ?
The solution to (3^{-4}x^0)/(y^{-8)} is (y^8)/(81)