What are the solutions to the equation x^2+10x=10 ?

The solutions to the equation x^2+10x=10 are x=-5+sqrt(35),x=-5-sqrt(35)

Find the zeros of x^2+10x=10

The zeros of x^2+10x=10 are x=-5+sqrt(35),x=-5-sqrt(35)

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x^{2} + 10 x = 10

x = - 5 + 35, x = - 5 - 35

Decimal Notation

x = 0.91607 \dots, x = - 10.91607 \dots

Solution steps

x^{2} + 10 x = 10

Move

10

to the left side

x^{2} + 10 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 10) = 235

x_{1, 2} = \frac{- 10 \pm 2 35}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 35}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 35}{2 \cdot 1}

x = \frac{- 10 + 2 35}{2 \cdot 1} : - 5 + 35

x = \frac{- 10 - 2 35}{2 \cdot 1} : - 5 - 35

The solutions to the quadratic equation are:

x = - 5 + 35, x = - 5 - 35

3.2 x^{2} - 7.1 x + 2.5 = 0

- 12 x^{2} + 48 x - 16 = 0

4 (x - 1)^{2} = (2 - x)^{2}

2 x^{2} + 19 x + 45 = 0

t^{2} - 2 t - 24 = 0

What are the solutions to the equation x^2+10x=10 ?
The solutions to the equation x^2+10x=10 are x=-5+sqrt(35),x=-5-sqrt(35)
Find the zeros of x^2+10x=10
The zeros of x^2+10x=10 are x=-5+sqrt(35),x=-5-sqrt(35)