What are the solutions to the equation 7=-x^2+16 ?

The solutions to the equation 7=-x^2+16 are x=3,x=-3

Find the zeros of 7=-x^2+16

The zeros of 7=-x^2+16 are x=3,x=-3

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7 = - x^{2} + 16

x = 3, x = - 3

Solution steps

7 = - x^{2} + 16

Switch sides

- x^{2} + 16 = 7

Move

16

to the right side

- x^{2} = - 9

Divide both sides by

- 1

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

5 x^{2} + 20 x + 8 = 0

m^{2} + 8 m + 6 = 0

8 x^{2} - 18 x + 7 = 0

5 x (x - 6) + 4 (x - 4) = - 7 x^{2} - 30

2 x^{2} - 28 x = - 98

What are the solutions to the equation 7=-x^2+16 ?
The solutions to the equation 7=-x^2+16 are x=3,x=-3
Find the zeros of 7=-x^2+16
The zeros of 7=-x^2+16 are x=3,x=-3