What are the solutions to the equation -5x^2=1 ?

The solutions to the equation -5x^2=1 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i

Find the zeros of -5x^2=1

The zeros of -5x^2=1 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i

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- 5 x^{2} = 1

x = \frac{1}{5} i, x = - \frac{1}{5} i

Solution steps

- 5 x^{2} = 1

Divide both sides by

- 5

x^{2} = - \frac{1}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{5}, x = - - \frac{1}{5}

- \frac{1}{5} = \frac{1}{5} i

- - \frac{1}{5} = - \frac{1}{5} i

x = \frac{1}{5} i, x = - \frac{1}{5} i

w^{2} + 14047 - 126504 = 0

4 (10 - x^{2}) = 5 x^{2}

10 x^{2} + 10 = 10

x, 153 x^{2} + 192 x y + 97 y^{2} = 225

x, x^{2} + y + z^{2} = 4

What are the solutions to the equation -5x^2=1 ?
The solutions to the equation -5x^2=1 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i
Find the zeros of -5x^2=1
The zeros of -5x^2=1 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i