What are the solutions to the equation 16+x^2=49 ?

The solutions to the equation 16+x^2=49 are x=sqrt(33),x=-sqrt(33)

Find the zeros of 16+x^2=49

The zeros of 16+x^2=49 are x=sqrt(33),x=-sqrt(33)

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16 + x^{2} = 49

x = 33, x = - 33

Decimal Notation

x = 5.74456 \dots, x = - 5.74456 \dots

Solution steps

16 + x^{2} = 49

Move

16

to the right side

x^{2} = 33

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 33, x = - 33

2 x^{2} - 14 x = - 15 - x^{2}

0 = - 4.9 x^{2} + 10 x + 100

x + x - \frac{xx}{100} = 36

2 x^{2} - 3 x - 5 = 0

x^{2} - \frac{1}{2} x + \frac{1}{4} = 0

What are the solutions to the equation 16+x^2=49 ?
The solutions to the equation 16+x^2=49 are x=sqrt(33),x=-sqrt(33)
Find the zeros of 16+x^2=49
The zeros of 16+x^2=49 are x=sqrt(33),x=-sqrt(33)