What are the solutions to the equation 3x^2+80x-1600=0 ?

The solutions to the equation 3x^2+80x-1600=0 are x= 40/3 ,x=-40

Find the zeros of 3x^2+80x-1600=0

The zeros of 3x^2+80x-1600=0 are x= 40/3 ,x=-40

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3 x^{2} + 80 x - 1600 = 0

x = \frac{40}{3}, x = - 40

Decimal Notation

x = 13.33333 \dots, x = - 40

Solution steps

3 x^{2} + 80 x - 1600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 3 ( - 1600 )}{2 \cdot 3}

8 0^{2} - 4 \cdot 3 (- 1600) = 160

x_{1, 2} = \frac{- 80 \pm 160}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 80 + 160}{2 \cdot 3}, x_{2} = \frac{- 80 - 160}{2 \cdot 3}

x = \frac{- 80 + 160}{2 \cdot 3} : \frac{40}{3}

x = \frac{- 80 - 160}{2 \cdot 3} : - 40

The solutions to the quadratic equation are:

x = \frac{40}{3}, x = - 40

4 (10 - x)^{2} = 5 x^{2}

x, 4 x^{2} - y^{2} + 4 z^{2} - 4 = 0

(5 x + 3) (2 x - 8) = 0

2 x^{2} + 3 = x^{2} - 2 x + 4

t, f = (5 t + 2) (t - 2)

What are the solutions to the equation 3x^2+80x-1600=0 ?
The solutions to the equation 3x^2+80x-1600=0 are x= 40/3 ,x=-40
Find the zeros of 3x^2+80x-1600=0
The zeros of 3x^2+80x-1600=0 are x= 40/3 ,x=-40