What are the solutions to the equation 2x^2+7x+16=0 ?

The solutions to the equation 2x^2+7x+16=0 are x=-7/4+i(sqrt(79))/4 ,x=-7/4-i(sqrt(79))/4

Find the zeros of 2x^2+7x+16=0

The zeros of 2x^2+7x+16=0 are x=-7/4+i(sqrt(79))/4 ,x=-7/4-i(sqrt(79))/4

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2 x^{2} + 7 x + 16 = 0

x = - \frac{7}{4} + i \frac{79}{4}, x = - \frac{7}{4} - i \frac{79}{4}

Solution steps

2 x^{2} + 7 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 16}{2 \cdot 2}

Simplify

7^{2} - 4 \cdot 2 \cdot 16 : 79 i

x_{1, 2} = \frac{- 7 \pm 79 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 79 i}{2 \cdot 2}, x_{2} = \frac{- 7 - 79 i}{2 \cdot 2}

x = \frac{- 7 + 79 i}{2 \cdot 2} : - \frac{7}{4} + i \frac{79}{4}

x = \frac{- 7 - 79 i}{2 \cdot 2} : - \frac{7}{4} - i \frac{79}{4}

The solutions to the quadratic equation are:

x = - \frac{7}{4} + i \frac{79}{4}, x = - \frac{7}{4} - i \frac{79}{4}

36 x^{2} - 40 = 9

7 b^{2} = 343

x^{2} + 8 x + 9 = 0

b^{2} + 110 b - 19.7 \cdot 1 0^{4} = 0

12 0^{2} + 5 0^{2} = x^{2}

What are the solutions to the equation 2x^2+7x+16=0 ?
The solutions to the equation 2x^2+7x+16=0 are x=-7/4+i(sqrt(79))/4 ,x=-7/4-i(sqrt(79))/4
Find the zeros of 2x^2+7x+16=0
The zeros of 2x^2+7x+16=0 are x=-7/4+i(sqrt(79))/4 ,x=-7/4-i(sqrt(79))/4