What are the solutions to the equation x(x+8)=12 ?

The solutions to the equation x(x+8)=12 are x=2(sqrt(7)-2),x=-2(2+sqrt(7))

Find the zeros of x(x+8)=12

The zeros of x(x+8)=12 are x=2(sqrt(7)-2),x=-2(2+sqrt(7))

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x (x + 8) = 12

x = 2 (7 - 2), x = - 2 (2 + 7)

Decimal Notation

x = 1.29150 \dots, x = - 9.29150 \dots

Solution steps

x (x + 8) = 12

Expand

x (x + 8) : x^{2} + 8 x

x^{2} + 8 x = 12

Move

12

to the left side

x^{2} + 8 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 12) = 47

x_{1, 2} = \frac{- 8 \pm 4 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 4 7}{2 \cdot 1}, x_{2} = \frac{- 8 - 4 7}{2 \cdot 1}

x = \frac{- 8 + 4 7}{2 \cdot 1} : 2 (7 - 2)

x = \frac{- 8 - 4 7}{2 \cdot 1} : - 2 (2 + 7)

The solutions to the quadratic equation are:

x = 2 (7 - 2), x = - 2 (2 + 7)

x^{2} + 2 x - 6 = 9

\frac{1}{25} h^{2} - 16 = 0

x, f (- 1 - 1) = x^{2} y^{2} - x^{2} y^{3} + 13

x, x^{2} = 25

w^{2} - 11 w + 30 = 0

What are the solutions to the equation x(x+8)=12 ?
The solutions to the equation x(x+8)=12 are x=2(sqrt(7)-2),x=-2(2+sqrt(7))
Find the zeros of x(x+8)=12
The zeros of x(x+8)=12 are x=2(sqrt(7)-2),x=-2(2+sqrt(7))