What are the solutions to the equation x^2=11x+126 ?

The solutions to the equation x^2=11x+126 are x=18,x=-7

Find the zeros of x^2=11x+126

The zeros of x^2=11x+126 are x=18,x=-7

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x^{2} = 11 x + 126

x = 18, x = - 7

Solution steps

x^{2} = 11 x + 126

Move

126

to the left side

x^{2} - 126 = 11 x

Move

11 x

to the left side

x^{2} - 126 - 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 11 x - 126 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot ( - 126 )}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot (- 126) = 25

x_{1, 2} = \frac{- ( - 11 ) \pm 25}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 25}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 25}{2 \cdot 1}

x = \frac{- ( - 11 ) + 25}{2 \cdot 1} : 18

x = \frac{- ( - 11 ) - 25}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 18, x = - 7

s^{2} + 16 s + 100 = 0

x^{2} - 6 = 19

- x^{2} + 2 x - 3 = 4

(2 x - 1) (3 x - 2) = 3

x, x^{2} + y^{2} + z^{2} + 9 x - 2 y + 10 z + 19 = 0

What are the solutions to the equation x^2=11x+126 ?
The solutions to the equation x^2=11x+126 are x=18,x=-7
Find the zeros of x^2=11x+126
The zeros of x^2=11x+126 are x=18,x=-7