What are the solutions to the equation 5c^2+4c-1=0 ?

The solutions to the equation 5c^2+4c-1=0 are c= 1/5 ,c=-1

Find the zeros of 5c^2+4c-1=0

The zeros of 5c^2+4c-1=0 are c= 1/5 ,c=-1

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5 c^{2} + 4 c - 1 = 0

c = \frac{1}{5}, c = - 1

Decimal Notation

c = 0.2, c = - 1

Solution steps

5 c^{2} + 4 c - 1 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

4^{2} - 4 \cdot 5 (- 1) = 6

c_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 5}

Separate the solutions

c_{1} = \frac{- 4 + 6}{2 \cdot 5}, c_{2} = \frac{- 4 - 6}{2 \cdot 5}

c = \frac{- 4 + 6}{2 \cdot 5} : \frac{1}{5}

c = \frac{- 4 - 6}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

c = \frac{1}{5}, c = - 1

- 400 (x)^{2} + 9600 x + 79200 = 0

0.6 x^{2} + 1.4 x - 1 = 0

2 x^{2} + 3 x + 2 = 0

a (x) = x^{2} + 1700 0^{-} 1

2 n^{2} + 12 n + 18 = 0

What are the solutions to the equation 5c^2+4c-1=0 ?
The solutions to the equation 5c^2+4c-1=0 are c= 1/5 ,c=-1
Find the zeros of 5c^2+4c-1=0
The zeros of 5c^2+4c-1=0 are c= 1/5 ,c=-1