What are the solutions to the equation -4x^2+2=0 ?

The solutions to the equation -4x^2+2=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of -4x^2+2=0

The zeros of -4x^2+2=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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- 4 x^{2} + 2 = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

- 4 x^{2} + 2 = 0

Move

2

to the right side

- 4 x^{2} = - 2

Divide both sides by

- 4

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

x, 5 x^{2} + 6 x y + 5 y^{2} - 8 = 0

(x + 2)^{2} = 6

x, x^{2} + y^{2} + y + 3 x = - 10

x^{2} + \frac{x}{5} = 0

r^{2} - 8 r + 12 = 0

What are the solutions to the equation -4x^2+2=0 ?
The solutions to the equation -4x^2+2=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of -4x^2+2=0
The zeros of -4x^2+2=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))