What are the solutions to the equation (9x+4)^2=16 ?

The solutions to the equation (9x+4)^2=16 are x=0,x=-8/9

Find the zeros of (9x+4)^2=16

The zeros of (9x+4)^2=16 are x=0,x=-8/9

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(9 x + 4)^{2} = 16

x = 0, x = - \frac{8}{9}

Decimal Notation

x = 0, x = - 0.88888 \dots

Solution steps

(9 x + 4)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

9 x + 4 = 16 : x = 0

Solve

9 x + 4 = - 16 : x = - \frac{8}{9}

The solutions to the quadratic equation are:

x = 0, x = - \frac{8}{9}

3 x (x + 5) = - 8

64 x^{2} - 121 = 0

y, (z - 4)^{2} = 4 y^{2}

20000 - 200 Q + Q^{2} = 20000 - 400 Q + 3 Q^{2}

1^{2} = 0. 8^{2} + c^{2}

What are the solutions to the equation (9x+4)^2=16 ?
The solutions to the equation (9x+4)^2=16 are x=0,x=-8/9
Find the zeros of (9x+4)^2=16
The zeros of (9x+4)^2=16 are x=0,x=-8/9