What is |x+1|>= |x| ?

The solution to |x+1|>= |x| is x>=-1/2

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|x+1|>= |x|

∣ x + 1 ∣ \geq ∣ x ∣

x \geq - \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \infty)

Decimal Notation

x \geq - 0.5

Solution steps

∣ x + 1 ∣ \geq ∣ x ∣

Find positive and negative intervals

x < - 1, - 1 \leq x < 0, x \geq 0

Solve the inequality for each interval

No Solution or - \frac{1}{2} \leq x < 0 or x \geq 0

Merge Overlapping Intervals

x \geq - \frac{1}{2}

4^{\frac{4}{3}}

x^{2} - 12 x y - 13 y^{2}

\frac{50 \cdot \frac{50}{3} - 3 ( \frac{50}{3} ) ^{2}}{4 π}

(3 - 2 x)^{2} \geq 4

8 x = 5 x + 15